4) (11 \frac{1}{2}-\frac{9}{19})\cdot 3; 9) 2 \frac{2}{25}\cdot 2+5 \frac{5}{25}\cdot 3; 11) 1 \frac{1}{4}:1 \frac{8}{12}-6 \frac{7}{73}\cdot 5 \frac{7}{7}; 13) 4 \frac{2}{5}-\frac{3}{4}+8 \frac{15}{15}-8 \frac{8}{60}; 14) \frac{7}{2}:2 \frac{2}{3}-12 \frac{1}{4}+\frac{3}{2}+2 \frac{2}{5}; 15) [(1 \frac{1}{2}+2 \frac{2}{3}):3 \frac{3}{4}-\frac{2}{5}]:8 \frac{8}{9}+4; 16) (3 \frac{1}{4}+2 \frac{1}{6}):2 \frac{3}{5}-2 \frac{4}{25}+5 \frac{1}{6}; 17) [1 \frac{1}{10}+7:(3 \frac{1}{12}-1 \frac{5}{8})].1 \frac{1}{59}; 18) 3 \frac{1}{4}:(14 \frac{4}{5}+\frac{3}{15})-47]:5 \frac{1}{10}; 19) (7 \frac{1}{3}-6 \frac{6}{8}):\frac{3}{4}-(5 \frac{3}{4}-4 \frac{4}{40}):1 \frac{1}{20}; 469. В следующих примерах произвести указания: 1) \frac{5}{6}:+\frac{1}{2}+2 \frac{1}{2}-1:1 \frac{1}{19}; 2) 2 \frac{3}{4}:(1 \frac{1}{2}-\frac{2}{5})+(\frac{3}{4}+\frac{5}{6}):3 \frac{1}{36}; 3) (\frac{2}{15}+1 \frac{1}{12})\cdot \frac{7}{103}-(2:2 \frac{1}{4})\cdot \frac{9}{32}; 4) (3:2 \frac{4}{3}+4 \frac{2}{3}:3 \frac{1}{2})\cdot 4 \frac{4}{5};

4) \[ (11 \frac{1}{2} - \frac{9}{19}) \cdot 3 = (\frac{23}{2} - \frac{9}{19}) \cdot 3 = (\frac{23 \cdot 19 - 9 \cdot 2}{2 \cdot 19}) \cdot 3 = (\frac{437 - 18}{38}) \cdot 3 = \frac{419}{38} \cdot 3 = \frac{419 \cdot 3}{38} = \frac{1257}{38} = 33 \frac{3}{38} \]

9) \[ 2 \frac{2}{25} \cdot 2 + 5 \frac{5}{25} \cdot 3 = \frac{52}{25} \cdot 2 + \frac{130}{25} \cdot 3 = \frac{52 \cdot 2}{25} + \frac{130 \cdot 3}{25} = \frac{104}{25} + \frac{390}{25} = \frac{104 + 390}{25} = \frac{494}{25} = 19 \frac{19}{25} \]

11) \[ 1 \frac{1}{4} : 1 \frac{8}{12} - 6 \frac{7}{73} \cdot 5 \frac{7}{7} = \frac{5}{4} : \frac{20}{12} - \frac{445}{73} \cdot \frac{36}{7} = \frac{5}{4} \cdot \frac{12}{20} - \frac{445 \cdot 36}{73 \cdot 7} = \frac{5 \cdot 12}{4 \cdot 20} - \frac{16020}{511} = \frac{60}{80} - \frac{16020}{511} = \frac{3}{4} - \frac{16020}{511} = \frac{3 \cdot 511 - 16020 \cdot 4}{4 \cdot 511} = \frac{1533 - 64080}{2044} = \frac{-62547}{2044} = -30 \frac{1227}{2044} \]

13) \[ 4 \frac{2}{5} - \frac{3}{4} + 8 \frac{15}{15} - 8 \frac{8}{60} = 4 \frac{2}{5} - \frac{3}{4} + 9 - 8 \frac{2}{15} = (4 + 9 - 8) + (\frac{2}{5} - \frac{3}{4} - \frac{2}{15}) = 5 + (\frac{2 \cdot 12 - 3 \cdot 15 - 2 \cdot 4}{60}) = 5 + (\frac{24 - 45 - 8}{60}) = 5 + (\frac{-29}{60}) = 5 - \frac{29}{60} = 4 \frac{31}{60} \]

14) \[ \frac{7}{2} : 2 \frac{2}{3} - 12 \frac{1}{4} + \frac{3}{2} + 2 \frac{2}{5} = \frac{7}{2} : \frac{8}{3} - \frac{49}{4} + \frac{3}{2} + \frac{12}{5} = \frac{7}{2} \cdot \frac{3}{8} - \frac{49}{4} + \frac{3}{2} + \frac{12}{5} = \frac{21}{16} - \frac{49}{4} + \frac{3}{2} + \frac{12}{5} = \frac{21 \cdot 5 - 49 \cdot 20 + 3 \cdot 40 + 12 \cdot 16}{80} = \frac{105 - 980 + 120 + 192}{80} = \frac{-563}{80} = -7 \frac{3}{80} \]

15) \[ [(1 \frac{1}{2} + 2 \frac{2}{3}) : 3 \frac{3}{4} - \frac{2}{5}] : 8 \frac{8}{9} + 4 = [(\frac{3}{2} + \frac{8}{3}) : \frac{15}{4} - \frac{2}{5}] : \frac{80}{9} + 4 = [(\frac{3 \cdot 3 + 8 \cdot 2}{6}) : \frac{15}{4} - \frac{2}{5}] : \frac{80}{9} + 4 = [(\frac{9 + 16}{6}) : \frac{15}{4} - \frac{2}{5}] : \frac{80}{9} + 4 = [\frac{25}{6} \cdot \frac{4}{15} - \frac{2}{5}] : \frac{80}{9} + 4 = [\frac{25 \cdot 4}{6 \cdot 15} - \frac{2}{5}] : \frac{80}{9} + 4 = [\frac{100}{90} - \frac{2}{5}] : \frac{80}{9} + 4 = [\frac{10}{9} - \frac{2}{5}] : \frac{80}{9} + 4 = [\frac{10 \cdot 5 - 2 \cdot 9}{45}] : \frac{80}{9} + 4 = \frac{50 - 18}{45} : \frac{80}{9} + 4 = \frac{32}{45} \cdot \frac{9}{80} + 4 = \frac{32 \cdot 9}{45 \cdot 80} + 4 = \frac{288}{3600} + 4 = \frac{4}{50} + 4 = \frac{2}{25} + 4 = 4 \frac{2}{25} \]

16) \[ (3 \frac{1}{4} + 2 \frac{1}{6}) : 2 \frac{3}{5} - 2 \frac{4}{25} + 5 \frac{1}{6} = (\frac{13}{4} + \frac{13}{6}) : \frac{13}{5} - \frac{54}{25} + \frac{31}{6} = \frac{13}{1} (\frac{1}{4} + \frac{1}{6}) \cdot \frac{5}{13} - \frac{54}{25} + \frac{31}{6} = (\frac{1 \cdot 3 + 1 \cdot 2}{12}) \cdot 5 - \frac{54}{25} + \frac{31}{6} = \frac{5}{12} \cdot 5 - \frac{54}{25} + \frac{31}{6} = \frac{25}{12} - \frac{54}{25} + \frac{31}{6} = \frac{25 \cdot 25 - 54 \cdot 12 + 31 \cdot 50}{300} = \frac{625 - 648 + 1550}{300} = \frac{1527}{300} = \frac{509}{100} = 5 \frac{9}{100} \]

17) \[ [1 \frac{1}{10} + 7 : (3 \frac{1}{12} - 1 \frac{5}{8})] \cdot 1 \frac{1}{59} = [\frac{11}{10} + 7 : (\frac{37}{12} - \frac{13}{8})] \cdot \frac{60}{59} = [\frac{11}{10} + 7 : (\frac{37 \cdot 2 - 13 \cdot 3}{24})] \cdot \frac{60}{59} = [\frac{11}{10} + 7 : (\frac{74 - 39}{24})] \cdot \frac{60}{59} = [\frac{11}{10} + 7 : \frac{35}{24}] \cdot \frac{60}{59} = [\frac{11}{10} + 7 \cdot \frac{24}{35}] \cdot \frac{60}{59} = [\frac{11}{10} + \frac{7 \cdot 24}{35}] \cdot \frac{60}{59} = [\frac{11}{10} + \frac{24}{5}] \cdot \frac{60}{59} = [\frac{11 + 24 \cdot 2}{10}] \cdot \frac{60}{59} = [\frac{11 + 48}{10}] \cdot \frac{60}{59} = \frac{59}{10} \cdot \frac{60}{59} = \frac{59 \cdot 60}{10 \cdot 59} = 6 \]

18) \[ 3 \frac{1}{4} : [(14 \frac{4}{5} + \frac{3}{15}) - 47] : 5 \frac{1}{10} = \frac{13}{4} : [(\frac{74}{5} + \frac{1}{5}) - 47] : \frac{51}{10} = \frac{13}{4} : [\frac{75}{5} - 47] : \frac{51}{10} = \frac{13}{4} : [15 - 47] : \frac{51}{10} = \frac{13}{4} : [-32] : \frac{51}{10} = \frac{13}{4} \cdot (\frac{-1}{32}) \cdot \frac{10}{51} = \frac{13 \cdot (-1) \cdot 10}{4 \cdot 32 \cdot 51} = \frac{-130}{6528} = \frac{-65}{3264} \]

19) \[ (7 \frac{1}{3} - 6 \frac{6}{8}) : \frac{3}{4} - (5 \frac{3}{4} - 4 \frac{4}{40}) : 1 \frac{1}{20} = (\frac{22}{3} - \frac{54}{8}) : \frac{3}{4} - (\frac{23}{4} - \frac{164}{40}) : \frac{21}{20} = (\frac{22}{3} - \frac{27}{4}) : \frac{3}{4} - (\frac{23}{4} - \frac{41}{10}) : \frac{21}{20} = (\frac{22 \cdot 4 - 27 \cdot 3}{12}) : \frac{3}{4} - (\frac{23 \cdot 5 - 41 \cdot 2}{20}) : \frac{21}{20} = (\frac{88 - 81}{12}) : \frac{3}{4} - (\frac{115 - 82}{20}) : \frac{21}{20} = \frac{7}{12} \cdot \frac{4}{3} - \frac{33}{20} \cdot \frac{20}{21} = \frac{7 \cdot 4}{12 \cdot 3} - \frac{33}{21} = \frac{28}{36} - \frac{33}{21} = \frac{7}{9} - \frac{11}{7} = \frac{7 \cdot 7 - 11 \cdot 9}{63} = \frac{49 - 99}{63} = \frac{-50}{63} \]

1) \[ \frac{5}{6} : \frac{5}{6} + 2 \frac{1}{2} - 1 : 1 \frac{1}{19} = 1 + \frac{5}{2} - 1 : \frac{20}{19} = 1 + \frac{5}{2} - 1 \cdot \frac{19}{20} = 1 + \frac{5}{2} - \frac{19}{20} = \frac{20 + 50 - 19}{20} = \frac{51}{20} = 2 \frac{11}{20} \]

2) \[ 2 \frac{3}{4} : (1 \frac{1}{2} - \frac{2}{5}) + (\frac{3}{4} + \frac{5}{6}) : 3 \frac{1}{36} = \frac{11}{4} : (\frac{3}{2} - \frac{2}{5}) + (\frac{3}{4} + \frac{5}{6}) : \frac{109}{36} = \frac{11}{4} : (\frac{3 \cdot 5 - 2 \cdot 2}{10}) + (\frac{3 \cdot 3 + 5 \cdot 2}{12}) : \frac{109}{36} = \frac{11}{4} : \frac{11}{10} + \frac{19}{12} : \frac{109}{36} = \frac{11}{4} \cdot \frac{10}{11} + \frac{19}{12} \cdot \frac{36}{109} = \frac{10}{4} + \frac{19 \cdot 3}{109} = \frac{5}{2} + \frac{57}{109} = \frac{5 \cdot 109 + 57 \cdot 2}{218} = \frac{545 + 114}{218} = \frac{659}{218} = 3 \frac{7}{218} \]

3) \[ (\frac{2}{15} + 1 \frac{1}{12}) \cdot \frac{7}{103} - (2 : 2 \frac{1}{4}) \cdot \frac{9}{32} = (\frac{2}{15} + \frac{13}{12}) \cdot \frac{7}{103} - (2 : \frac{9}{4}) \cdot \frac{9}{32} = (\frac{2 \cdot 4 + 13 \cdot 5}{60}) \cdot \frac{7}{103} - (2 \cdot \frac{4}{9}) \cdot \frac{9}{32} = \frac{8 + 65}{60} \cdot \frac{7}{103} - \frac{8}{9} \cdot \frac{9}{32} = \frac{73}{60} \cdot \frac{7}{103} - \frac{8}{32} = \frac{511}{6180} - \frac{1}{4} = \frac{511 - 1545}{6180} = \frac{-1034}{6180} = \frac{-517}{3090} \]

4) \[ (3 : 2 \frac{4}{3} + 4 \frac{2}{3} : 3 \frac{1}{2}) \cdot 4 \frac{4}{5} = (3 : \frac{10}{3} + \frac{14}{3} : \frac{7}{2}) \cdot \frac{24}{5} = (3 \cdot \frac{3}{10} + \frac{14}{3} \cdot \frac{2}{7}) \cdot \frac{24}{5} = (\frac{9}{10} + \frac{4}{3}) \cdot \frac{24}{5} = (\frac{9 \cdot 3 + 4 \cdot 10}{30}) \cdot \frac{24}{5} = (\frac{27 + 40}{30}) \cdot \frac{24}{5} = \frac{67}{30} \cdot \frac{24}{5} = \frac{67 \cdot 24}{30 \cdot 5} = \frac{1608}{150} = \frac{804}{75} = \frac{268}{25} = 10 \frac{18}{25} \]